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TorChase

last edited 1 year ago by admin

One can use \text{Tor} to show easily that if is exact with C flat then it is pure exact. This requires knowing that \text{Tor} is balanced (indeed even well defined) and so we give a simple diagram chase argument instead. We hope that this chase gives some indication as to how the chases proceed to prove the general theory of \text{Tor}.

Let R be an associative ring with 1, and F a left R-module. We say that F is flat if given any exact sequence of right R-modules , then is an exact sequence of Abelian groups. Similarly an exact sequence of right R-modules is said to be pure exact if 0 \to {A \otimes E} \to B \otimes E \to C \otimes E \to 0 is an exact sequence of Abelian groups for every left R-module E.

Suppose F is flat and is exact. We want to show it is pure exact, so we let A be a right R-module. The tensor product is already right exact so we at least have the following exact sequence: . By the general theory of \text{Tor}, we know that , but we wish to prove this directly.

We consider a partial flat resolution of A, that is an exact sequence with B flat (for instance the free right R-module R^{(A)}). We can form the somewhat large commutative diagram with exact rows and columns:

 

Let . Since , for some . Since we get \phi(x_1) \in \ker(d) = \text{im}(i), so for some . , so , so , so for some . , so x_1 - h(x_3) \in \ker(\phi) = 0, so . Thus .

Thus and is exact, and thus is pure.

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2004-01-24