History for BlaBla

??changed:
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Test
\begin{equation}
\begin{array}{l}
 P\left( {2|gerade} \right) = \frac{{P\left( {2 \cap gerade} \right)}}{{P\left( {gerade} \right)}} = \frac{{P\left( 2 \right) \cdot P\left( {gerade|2} \right)}}{{P\left( 1 \right) \cdot P\left( {gerade|1} \right) + P\left( 2 \right) \cdot P\left( {gerade|2} \right) + P\left( 3 \right) \cdot P\left( {gerade|3} \right) + P\left( 4 \right) \cdot P\left( {gerade|4} \right) + P\left( 5 \right) \cdot P\left( {gerade|5} \right) + P\left( 6 \right) \cdot P\left( {gerade|6} \right)}} \\ 
  = \frac{{\frac{1}{6} \cdot 1}}{{0 + \frac{1}{6} \cdot 1 + 0 + \frac{1}{6} \cdot 1 + 0 + \frac{1}{6} \cdot 1}} = \frac{{\frac{1}{6}}}{{\frac{1}{{18}}}} = \frac{1}{3} \\ 
 \end{array}
\end{equation}